Use Json.Net for MVC ValueProviderFactory

This commit is contained in:
Gary Sharp
2016-10-06 19:39:19 +11:00
parent e082c22983
commit 1dfa3f4f15
13 changed files with 51 additions and 45 deletions
@@ -15,7 +15,6 @@
<TargetFrameworkProfile />
<SolutionDir Condition="$(SolutionDir) == '' Or $(SolutionDir) == '*Undefined*'">..\</SolutionDir>
<RestorePackages>true</RestorePackages>
<AssemblyVersion>2.2.16272.1003</AssemblyVersion>
</PropertyGroup>
<PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Debug|AnyCPU' ">
<DebugSymbols>true</DebugSymbols>
@@ -104,6 +103,7 @@
<Compile Include="DataModelExtension\DocumentTemplateExtensions.cs" />
<Compile Include="DataModelExtension\JobSubTypeExtensions.cs" />
<Compile Include="DataModelExtension\JobTypeExtensions.cs" />
<Compile Include="MvcExtensions\JsonNet\JsonDotNetValueProviderFactory.cs" />
<Compile Include="MvcExtensions\JsonNet\JsonNetResult.cs" />
<Compile Include="MvcExtensions\PartialCompiled\PartialCompiledHtmlExtensions.cs" />
<Compile Include="Properties\AssemblyInfo.cs" />
@@ -0,0 +1,38 @@
using Newtonsoft.Json;
using Newtonsoft.Json.Converters;
using System;
using System.Dynamic;
using System.Globalization;
using System.IO;
using System.Text;
using System.Web.Mvc;
namespace Disco.Web.Extensions
{
public class JsonDotNetValueProviderFactory : ValueProviderFactory
{
public override IValueProvider GetValueProvider(ControllerContext controllerContext)
{
if (controllerContext == null)
throw new ArgumentNullException(nameof(controllerContext));
if (!controllerContext.HttpContext.Request.ContentType.StartsWith("application/json", StringComparison.OrdinalIgnoreCase))
return null;
if (controllerContext.HttpContext.Request.InputStream.Length == 0)
return null;
var jsonSerializer = new JsonSerializer();
jsonSerializer.Converters.Add(new ExpandoObjectConverter());
using (var streamReader = new StreamReader(controllerContext.HttpContext.Request.InputStream, Encoding.UTF8, true, 0x400, true))
{
using (var jsonReader = new JsonTextReader(streamReader))
{
var bodyObject = jsonSerializer.Deserialize<ExpandoObject>(jsonReader);
return new DictionaryValueProvider<object>(bodyObject, CultureInfo.CurrentCulture);
}
}
}
}
}